MATHS :: Lecture 03 :: Bionomial
BINOMIAL THEOREM
A Binomial is an algebraic expression of two terms which are connected by the operation ‘+’ (or) ‘-‘
For example, x+siny, 3x2+2x, cosx+sin x etc… are binomials.
Binomial Theorem for positive integer:
If n is a positive integer then
----(1) |
Some Expansions
a) If we put a = -a in the place of a in
![]()
b) Put x =1 and a = x in (1)
----------(2)
c) Put x = 1 and a = -x in (1)
-----------(3)
(d) Replacing n by – n in equation (2)
---------(4)
e) Replacing n by – n in equation (3)
-----------(5)
Special Cases
1. ![]()
2. ![]()
3. ![]()
4. ![]()
Note:
1. There are n+1 terms in the expansion of (x+a)n.
2. In the expansion the general term is
. Since this is the (r+1)th term, it is denoted by Tr+1 i.e.
.
3.
are called binomial coefficients.
4. From the relation
, we see that the coefficients of terms equidistant from the beginning and the end are equal.
Note: The number of terms in the expansion of (x+a)n depends upon the index n. the index is either even (or) odd. Then the middle term is
Case(i): n is even
The number of terms in the expansion is (n+1), which is odd.
Therefore, there is only one middle term and is given by ![]()
Case(ii) : n is odd
The number of terms in the expansion is (n+1), which is even.
Therefore, there are two middle terms and they are given by
and
Examples
1. Expand (i)
2. Find 117.
Solution:
117= (1+10)7


= 1+ 70 + 2100 +35000 + 350000 + 2100000 + 7000000 + 10000000
= 19487171
2. Find the coefficient of x5 in the expansion of ![]()
Solution
In the expansion of
, the general term is
![]()
![]()
Let
be the term containing x5
then, 17-4r = 5 Þ r = 3
\
=![]()
= 680 x5
\coefficient of x5 = 680.
3. Find the constant term in the expansion of ![]()
Solution
In the expansion of
, the general term is
![]()
![]()
![]()
Let
be the Constant term then,
= 0Þ r = 2
\ The constant term
=
= 180
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